LeetCode 1784 | Check if Binary String Has at Most One Segment of Ones | Day 65/365 | C++

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YouTube Excerpt: 😄 Binary strings again causing drama… this time we’re checking if the 1’s stay together like a disciplined group! 💻⚡ LeetCode 1784 | Check if Binary String Has at Most One Segment of Ones | Daily LeetCode | Day 65/365 | String Traversal | C++ Solution In today’s video, we solve LeetCode 1784: Check if Binary String Has at Most One Segment of Ones. A binary string is considered valid if all the 1’s appear in a single continuous segment. If we ever see a 1 again after a 0 following a segment of 1’s, then the condition is violated. 🧠 Core Idea: ✔ Traverse the string once ✔ Track when the first segment of 1s ends ✔ If another 1 appears later → return false This is a simple yet important string traversal and pattern checking problem often asked in coding interviews. 📌 What you’ll learn in this video: • Understanding segments in binary strings • Detecting pattern breaks efficiently • One-pass string traversal approach • Clean C++ implementation • Time & space complexity explanation ⏱ Time Complexity: O(n) 💾 Space Complexity: O(1) 💻 Problem Link: https://leetcode.com/problems/check-if-binary-string-has-at-most-one-segment-of-ones/ ⸻ 🚀 Keywords for Search: LeetCode 1784 solution Check if Binary String Has at Most One Segment of Ones C++ Binary string segment problem LeetCode string problems explained Daily LeetCode challenge solution DSA string pattern problems Coding interview string questions Binary string traversal algorithm 🔖 Hashtags: #LeetCode #LeetCode1784 #DailyLeetCode #Day65of365 #BinaryString #StringProblems #DSA #CodingInterview #CPlusPlus #Programming 👍 Like if this explanation made binary strings easier 💬 Comment your approach or doubts 🔔 Subscribe to follow the 365 Days of LeetCode Challenge

😄 Binary strings again causing drama… this time we’re checking if the 1’s stay together like a disciplined group! 💻⚡ LeetCode 1784 | Check if...

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